What is the RPM of a 4 pole, 60 Hz motor?

Prepare for the CWEA Electrical and Instrumentation Grade 2 Test. Strengthen your skills with interactive questions and detailed explanations. Ensure your success!

To determine the RPM (revolutions per minute) of a motor, you can use the formula for synchronous speed, which is given by:

[ \text{Synchronous Speed (RPM)} = \frac{120 \times \text{Frequency (Hz)}}{\text{Number of Poles}} ]

For a motor with 4 poles and operating at a frequency of 60 Hz, you substitute the values into the formula:

[ \text{RPM} = \frac{120 \times 60}{4} ]

Calculating that gives:

[ \text{RPM} = \frac{7200}{4} = 1800 \text{ RPM} ]

This calculation indicates that a 4 pole, 60 Hz motor operates at a synchronous speed of 1800 RPM, which is why the correct answer is identified as 1800 RPM. This value represents the theoretical maximum speed of the motor under ideal conditions, not accounting for slip due to load conditions.

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