What is the amperage when 1000 Watts is pulled through a resistance of 12.5 ohms?

Prepare for the CWEA Electrical and Instrumentation Grade 2 Test. Strengthen your skills with interactive questions and detailed explanations. Ensure your success!

To find the amperage when 1000 Watts is pulled through a resistance of 12.5 ohms, you can use the formula derived from Ohm's Law and the power formula:

  1. Power (P) can be expressed as P = V * I, where V is voltage and I is current (amperage).
  1. Ohm's Law states that V = I * R, where R is resistance in ohms.

From these two formulas, we can combine them to express power in terms of resistance and current:

P = I^2 * R

Rearranging this gives:

I^2 = P / R

Now substituting the given values:

I^2 = 1000 Watts / 12.5 ohms

I^2 = 80

Next, I can be found by taking the square root:

I = √80 = 8.9442... amps

For simplicity, rounding it gives approximately 8.9 amps. Thus, this is the correct calculation leading to the conclusion that the amperage is approximately 8.9 amps. This demonstrates the relationship between power, current, and resistance in electrical circuits and reinforces the concept of how to utilize these formulas correctly.

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